(1a+1)/2=(2a-1)/5

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Solution for (1a+1)/2=(2a-1)/5 equation: 



(1a+1)/2=(2a-1)/5

We move all terms to the left:

(1a+1)/2-((2a-1)/5)=0

We add all the numbers together, and all the variables

(a+1)/2-((2a-1)/5)=0

We calculate fractions


a/()+(-((2a-1)*2)/()=0



We calculate terms in parentheses: +(-((2a-1)*2)/(), so:

-((2a-1)*2)/(

We multiply all the terms by the denominator


-((2a-1)*2)



We calculate terms in parentheses: -((2a-1)*2), so:

(2a-1)*2

We multiply parentheses

4a-2

Back to the equation:

-(4a-2)



We get rid of parentheses

-4a+2

Back to the equation:

+(-4a+2)



We get rid of parentheses

a/()-4a+2=0

We multiply all the terms by the denominator


a-4a*()+2*()=0

We add all the numbers together, and all the variables

a-4a*()=0

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