8(h+2)+h=5(h+4)

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Solution for 8(h+2)+h=5(h+4) equation: 



8(h+2)+h=5(h+4)

We move all terms to the left:

8(h+2)+h-(5(h+4))=0

We add all the numbers together, and all the variables

h+8(h+2)-(5(h+4))=0

We multiply parentheses

h+8h-(5(h+4))+16=0



We calculate terms in parentheses: -(5(h+4)), so:

5(h+4)

We multiply parentheses

5h+20

Back to the equation:

-(5h+20)



We add all the numbers together, and all the variables

9h-(5h+20)+16=0

We get rid of parentheses

9h-5h-20+16=0

We add all the numbers together, and all the variables

4h-4=0

We move all terms containing h to the left, all other terms to the right

4h=4

h=4/4

h=1

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