3b-62+1/5=180

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Solution for 3b-62+1/5=180 equation: 



3b-62+1/5=180

We move all terms to the left:

3b-62+1/5-(180)=0

determiningTheFunctionDomain
3b-62-180+1/5=0

We add all the numbers together, and all the variables

3b-242+1/5=0

We multiply all the terms by the denominator


3b*5+1-242*5=0

We add all the numbers together, and all the variables

3b*5-1209=0

Wy multiply elements

15b-1209=0

We move all terms containing b to the left, all other terms to the right

15b=1209

b=1209/15

b=80+3/5

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