(r-3)+(r+5)=10

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Solution for (r-3)+(r+5)=10 equation: 



(r-3)+(r+5)=10

We move all terms to the left:

(r-3)+(r+5)-(10)=0

We get rid of parentheses

r+r-3+5-10=0

We add all the numbers together, and all the variables

2r-8=0

We move all terms containing r to the left, all other terms to the right

2r=8

r=8/2

r=4

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