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3b-6((15+2b)/7)=2
We move all terms to the left:
3b-6((15+2b)/7)-(2)=0
We add all the numbers together, and all the variables
3b-6((2b+15)/7)-2=0
We multiply all the terms by the denominator
3b*7)-6((2b+15)-2*7)=0
We add all the numbers together, and all the variables
3b*7)-6((2b+15)=0
Wy multiply elements
21b^2=0
a = 21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·21·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{0}{42}=0$
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