3b-2(b-7)=3+2b

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Solution for 3b-2(b-7)=3+2b equation: 



3b-2(b-7)=3+2b

We move all terms to the left:

3b-2(b-7)-(3+2b)=0

We add all the numbers together, and all the variables

3b-2(b-7)-(2b+3)=0

We multiply parentheses

3b-2b-(2b+3)+14=0

We get rid of parentheses

3b-2b-2b-3+14=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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