(x+1)/5=(x+2)/15

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Solution for (x+1)/5=(x+2)/15 equation: 



(x+1)/5=(x+2)/15

We move all terms to the left:

(x+1)/5-((x+2)/15)=0

We calculate fractions


x/()+(-((x+2)*5)/()=0



We calculate terms in parentheses: +(-((x+2)*5)/(), so:

-((x+2)*5)/(

We multiply all the terms by the denominator


-((x+2)*5)



We calculate terms in parentheses: -((x+2)*5), so:

(x+2)*5

We multiply parentheses

5x+10

Back to the equation:

-(5x+10)



We get rid of parentheses

-5x-10

Back to the equation:

+(-5x-10)



We get rid of parentheses

x/()-5x-10=0

We multiply all the terms by the denominator


x-5x*()-10*()=0

We add all the numbers together, and all the variables

x-5x*()=0

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