3b-15/3=6/b

Solution for 3b-15/3=6/b equation:

3b-15/3=6/b

We move all terms to the left:

3b-15/3-(6/b)=0


Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

3b-(+6/b)-15/3=0

We add all the numbers together, and all the variables

3b-(+6/b)-5=0

We get rid of parentheses

3b-6/b-5=0

We multiply all the terms by the denominator


3b*b-5*b-6=0

We add all the numbers together, and all the variables

-5b+3b*b-6=0

Wy multiply elements

3b^2-5b-6=0

a = 3; b = -5; c = -6;
Δ = b2-4ac
Δ = -52-4·3·(-6)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{97}}{2*3}=\frac{5-\sqrt{97}}{6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{97}}{2*3}=\frac{5+\sqrt{97}}{6}
$