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3b+10=7-(6b-6)
We move all terms to the left:
3b+10-(7-(6b-6))=0
We calculate terms in parentheses: -(7-(6b-6)), so:We get rid of parentheses
7-(6b-6)
determiningTheFunctionDomain -(6b-6)+7
We get rid of parentheses
-6b+6+7
We add all the numbers together, and all the variables
-6b+13
Back to the equation:
-(-6b+13)
3b+6b-13+10=0
We add all the numbers together, and all the variables
9b-3=0
We move all terms containing b to the left, all other terms to the right
9b=3
b=3/9
b=1/3
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