x2=10x-12=(x=5)2+3x+2

Solution for x2=10x-12=(x=5)2+3x+2 equation:

x2=10x-12=(x=5)2+3x+2

We move all terms to the left:

x2-(10x-12)=0

We add all the numbers together, and all the variables

x^2-(10x-12)=0

We get rid of parentheses

x^2-10x+12=0

a = 1; b = -10; c = +12;
Δ = b2-4ac
Δ = -102-4·1·12
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{13}}{2*1}=\frac{10-2\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{13}}{2*1}=\frac{10+2\sqrt{13}}{2}
$