3b+(-5)=10

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Solution for 3b+(-5)=10 equation: 



3b+(-5)=10

We move all terms to the left:

3b+(-5)-(10)=0

determiningTheFunctionDomain
3b-10+(-5)=0

We add all the numbers together, and all the variables

3b-15=0

We move all terms containing b to the left, all other terms to the right

3b=15

b=15/3

b=5

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