X-5+3x+29+2/3x+8=360

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Solution for X-5+3x+29+2/3x+8=360 equation:



X-5+3X+29+2/3X+8=360
We move all terms to the left:
X-5+3X+29+2/3X+8-(360)=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
We add all the numbers together, and all the variables
4X+2/3X-328=0
We multiply all the terms by the denominator
4X*3X-328*3X+2=0
Wy multiply elements
12X^2-984X+2=0
a = 12; b = -984; c = +2;
Δ = b2-4ac
Δ = -9842-4·12·2
Δ = 968160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{968160}=\sqrt{16*60510}=\sqrt{16}*\sqrt{60510}=4\sqrt{60510}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-984)-4\sqrt{60510}}{2*12}=\frac{984-4\sqrt{60510}}{24} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-984)+4\sqrt{60510}}{2*12}=\frac{984+4\sqrt{60510}}{24} $

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