3a=2(a-5)+12

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Solution for 3a=2(a-5)+12 equation: 



3a=2(a-5)+12

We move all terms to the left:

3a-(2(a-5)+12)=0



We calculate terms in parentheses: -(2(a-5)+12), so:

2(a-5)+12

We multiply parentheses

2a-10+12

We add all the numbers together, and all the variables

2a+2

Back to the equation:

-(2a+2)



We get rid of parentheses

3a-2a-2=0

We add all the numbers together, and all the variables

a-2=0

We move all terms containing a to the left, all other terms to the right

a=2

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