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5/2x-2=9/2-2(x+1)
We move all terms to the left:
5/2x-2-(9/2-2(x+1))=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2-2(x+1))!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
-2(x+1))!=-2
x∈R
(-2(x+1))+5*2)/2x+(-(9*2x)/2x-2=0
We calculate terms in parentheses: +(-2(x+1)), so:We add all the numbers together, and all the variables
-2(x+1)
We multiply parentheses
-2x-2
Back to the equation:
+(-2x-2)
(-2x-2)+5*2)/2x+(-(+9*2x)/2x-2=0
We get rid of parentheses
-2x+5*2)/2x+(-(+9*2x)/2x-2-2=0
We calculate fractions
20x^2/(2x+(*2x)+(-36x^2)/(2x+(*2x)-2x-2-2=0
We can not solve this equation
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