If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3a^2+14a-5=0
a = 3; b = 14; c = -5;
Δ = b2-4ac
Δ = 142-4·3·(-5)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-16}{2*3}=\frac{-30}{6} =-5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+16}{2*3}=\frac{2}{6} =1/3 $
| (d=3+D=3) | | h3.5=9 | | R*2+8r-9=0 | | -75.1=31.5-4.2x | | 9x-8-11x=2+5x+4 | | R*2+8x-9=0 | | -3x+4=x-7 | | D=9^2-4x4x1x18 | | R2+8x-9=0 | | H=-16t^2+52t+30 | | 3(2x-1)+5x=52 | | 15x+100-25=165 | | 65=5e | | 0.14(y-5)+0.08y=0.02y-0.9 | | -10(2q+3)=-90 | | 60=-2n | | n-7/2=8n=4n | | n-3.5=8n=4n | | 35b^2-37b-6=0 | | 7=14y-7y | | A+5=4a-4 | | |4x+9|=45 | | 32-x=5x-10 | | y.3(y+1)+4=2(y-1)=y+y | | 5x-1=3(2x) | | 16^2x-3=32 | | -3(n-2)=12 | | 3^5x-1=9^2x | | 7x-4=12÷-1 | | 2^x-3=2^2x15 | | 3(2c+55)=4(c-3) | | 14x+8=6x-16 |