3(2c+55)=4(c-3)

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Solution for 3(2c+55)=4(c-3) equation: 



3(2c+55)=4(c-3)

We move all terms to the left:

3(2c+55)-(4(c-3))=0

We multiply parentheses

6c-(4(c-3))+165=0



We calculate terms in parentheses: -(4(c-3)), so:

4(c-3)

We multiply parentheses

4c-12

Back to the equation:

-(4c-12)



We get rid of parentheses

6c-4c+12+165=0

We add all the numbers together, and all the variables

2c+177=0

We move all terms containing c to the left, all other terms to the right

2c=-177

c=-177/2

c=-88+1/2

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