3a-5=4(5a-3)

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Solution for 3a-5=4(5a-3) equation: 



3a-5=4(5a-3)

We move all terms to the left:

3a-5-(4(5a-3))=0



We calculate terms in parentheses: -(4(5a-3)), so:

4(5a-3)

We multiply parentheses

20a-12

Back to the equation:

-(20a-12)



We get rid of parentheses

3a-20a+12-5=0

We add all the numbers together, and all the variables

-17a+7=0

We move all terms containing a to the left, all other terms to the right

-17a=-7

a=-7/-17

a=7/17

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