1x+(1x+1)+(1x+2)=63

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Solution for 1x+(1x+1)+(1x+2)=63 equation: 



1x+(1x+1)+(1x+2)=63

We move all terms to the left:

1x+(1x+1)+(1x+2)-(63)=0

We add all the numbers together, and all the variables

1x+(x+1)+(x+2)-63=0

We add all the numbers together, and all the variables

x+(x+1)+(x+2)-63=0

We get rid of parentheses

x+x+x+1+2-63=0

We add all the numbers together, and all the variables

3x-60=0

We move all terms containing x to the left, all other terms to the right

3x=60

x=60/3

x=20

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