3a-4+5a+7+2(a=1)=

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Solution for 3a-4+5a+7+2(a=1)= equation:



3a-4+5a+7+2(a=1)=
We move all terms to the left:
3a-4+5a+7+2(a-(1))=0
We add all the numbers together, and all the variables
8a+2(a-1)+3=0
We multiply parentheses
8a+2a-2+3=0
We add all the numbers together, and all the variables
10a+1=0
We move all terms containing a to the left, all other terms to the right
10a=-1
a=-1/10
a=-1/10

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