(10b-2)-3(3b+3)=-6

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Solution for (10b-2)-3(3b+3)=-6 equation: 



(10b-2)-3(3b+3)=-6

We move all terms to the left:

(10b-2)-3(3b+3)-(-6)=0

We add all the numbers together, and all the variables

(10b-2)-3(3b+3)+6=0

We multiply parentheses

(10b-2)-9b-9+6=0

We get rid of parentheses

10b-9b-2-9+6=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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