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3a+3(a-2)=2(4+a)-10
We move all terms to the left:
3a+3(a-2)-(2(4+a)-10)=0
We add all the numbers together, and all the variables
3a+3(a-2)-(2(a+4)-10)=0
We multiply parentheses
3a+3a-(2(a+4)-10)-6=0
We calculate terms in parentheses: -(2(a+4)-10), so:We add all the numbers together, and all the variables
2(a+4)-10
We multiply parentheses
2a+8-10
We add all the numbers together, and all the variables
2a-2
Back to the equation:
-(2a-2)
6a-(2a-2)-6=0
We get rid of parentheses
6a-2a+2-6=0
We add all the numbers together, and all the variables
4a-4=0
We move all terms containing a to the left, all other terms to the right
4a=4
a=4/4
a=1
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