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x*4x=2600
We move all terms to the left:
x*4x-(2600)=0
Wy multiply elements
4x^2-2600=0
a = 4; b = 0; c = -2600;
Δ = b2-4ac
Δ = 02-4·4·(-2600)
Δ = 41600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{41600}=\sqrt{1600*26}=\sqrt{1600}*\sqrt{26}=40\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{26}}{2*4}=\frac{0-40\sqrt{26}}{8} =-\frac{40\sqrt{26}}{8} =-5\sqrt{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{26}}{2*4}=\frac{0+40\sqrt{26}}{8} =\frac{40\sqrt{26}}{8} =5\sqrt{26} $
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