3a+1/3(6a-9)=1/2(10a-6)

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Solution for 3a+1/3(6a-9)=1/2(10a-6) equation: 



3a+1/3(6a-9)=1/2(10a-6)

We move all terms to the left:

3a+1/3(6a-9)-(1/2(10a-6))=0



Domain of the equation: 3(6a-9)!=0

a∈R





Domain of the equation: 2(10a-6))!=0

a∈R



We calculate fractions


3a+(2a1/(3(6a-9)*2(10a-6)))+(-3a6/(3(6a-9)*2(10a-6)))=0



We calculate terms in parentheses: +(2a1/(3(6a-9)*2(10a-6))), so:

2a1/(3(6a-9)*2(10a-6))

We multiply all the terms by the denominator


2a1

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-3a6/(3(6a-9)*2(10a-6))), so:

-3a6/(3(6a-9)*2(10a-6))

We multiply all the terms by the denominator


-3a6

We add all the numbers together, and all the variables

-3a^6

We do not support eapression: a^6

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