3Y=((8-12y)/4)+2

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Solution for 3Y=((8-12y)/4)+2 equation: 



3=((8-12Y)/4)+2

We move all terms to the left:

3-(((8-12Y)/4)+2)=0

We add all the numbers together, and all the variables

-(((-12Y+8)/4)+2)+3=0

We multiply all the terms by the denominator


-(((-12Y+8)+3*4)+2)=0



We calculate terms in parentheses: -(((-12Y+8)+3*4)+2), so:

((-12Y+8)+3*4)+2



We calculate terms in parentheses: +((-12Y+8)+3*4), so:

(-12Y+8)+3*4

We add all the numbers together, and all the variables

(-12Y+8)+12

We get rid of parentheses

-12Y+8+12

We add all the numbers together, and all the variables

-12Y+20

Back to the equation:

+(-12Y+20)



We get rid of parentheses

-12Y+20+2

We add all the numbers together, and all the variables

-12Y+22

Back to the equation:

-(-12Y+22)



We get rid of parentheses

12Y-22=0

We move all terms containing Y to the left, all other terms to the right

12Y=22

Y=22/12

Y=1+5/6

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