-5(z+6)-(1-3z)=(-3z)

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Solution for -5(z+6)-(1-3z)=(-3z) equation: 



-5(z+6)-(1-3z)=(-3z)

We move all terms to the left:

-5(z+6)-(1-3z)-((-3z))=0

We add all the numbers together, and all the variables

-5(z+6)-(-3z+1)-((-3z))=0

We multiply parentheses

-5z-(-3z+1)-((-3z))-30=0

We get rid of parentheses

-5z+3z-((-3z))-1-30=0



We calculate terms in parentheses: -((-3z)), so:

(-3z)

We get rid of parentheses

-3z

Back to the equation:

-(-3z)



We add all the numbers together, and all the variables

-2z-(-3z)-31=0

We get rid of parentheses

-2z+3z-31=0

We add all the numbers together, and all the variables

z-31=0

We move all terms containing z to the left, all other terms to the right

z=31

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