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3X^2-48X+9=180
We move all terms to the left:
3X^2-48X+9-(180)=0
We add all the numbers together, and all the variables
3X^2-48X-171=0
a = 3; b = -48; c = -171;
Δ = b2-4ac
Δ = -482-4·3·(-171)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-66}{2*3}=\frac{-18}{6} =-3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+66}{2*3}=\frac{114}{6} =19 $
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