5(b+3)=3(3b+5)

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Solution for 5(b+3)=3(3b+5) equation: 



5(b+3)=3(3b+5)

We move all terms to the left:

5(b+3)-(3(3b+5))=0

We multiply parentheses

5b-(3(3b+5))+15=0



We calculate terms in parentheses: -(3(3b+5)), so:

3(3b+5)

We multiply parentheses

9b+15

Back to the equation:

-(9b+15)



We get rid of parentheses

5b-9b-15+15=0

We add all the numbers together, and all the variables

-4b=0

b=0/-4

b=0

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