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3/(1+5H)=-1
We move all terms to the left:
3/(1+5H)-(-1)=0
Domain of the equation: (1+5H)!=0We add all the numbers together, and all the variables
We move all terms containing H to the left, all other terms to the right
5H!=-1
H!=-1/5
H!=-1/5
H∈R
3/(5H+1)-(-1)=0
We add all the numbers together, and all the variables
3/(5H+1)+1=0
We multiply all the terms by the denominator
1*(5H+1)+3=0
We move all terms containing H to the left, all other terms to the right
1*(5H+1)=-3
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