32-8z=5(z-4)

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Solution for 32-8z=5(z-4) equation: 



32-8z=5(z-4)

We move all terms to the left:

32-8z-(5(z-4))=0



We calculate terms in parentheses: -(5(z-4)), so:

5(z-4)

We multiply parentheses

5z-20

Back to the equation:

-(5z-20)



We get rid of parentheses

-8z-5z+20+32=0

We add all the numbers together, and all the variables

-13z+52=0

We move all terms containing z to the left, all other terms to the right

-13z=-52

z=-52/-13

z=+4

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