3=-4/3(-7)+b

Solution for 3=-4/3(-7)+b equation:

3=-4/3(-7)+b

We move all terms to the left:

3-(-4/3(-7)+b)=0


Domain of the equation: 3(-7)+b)!=0

b∈R


We multiply all the terms by the denominator


-(-4+3*3(-7)+b)=0


We calculate terms in parentheses: -(-4+3*3(-7)+b), so:

-4+3*3(-7)+b

determiningTheFunctionDomain
b-4+3*3(-7)

We add all the numbers together, and all the variables

b-67

Back to the equation:

-(b-67)


We get rid of parentheses

-b+67=0

We add all the numbers together, and all the variables

-1b+67=0

We move all terms containing b to the left, all other terms to the right

-b=-67

b=-67/-1

b=+67