3=+2(8-k)=3k-1

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Solution for 3=+2(8-k)=3k-1 equation: 



3=+2(8-k)=3k-1

We move all terms to the left:

3-(+2(8-k))=0

We add all the numbers together, and all the variables

-(+2(-1k+8))+3=0



We calculate terms in parentheses: -(+2(-1k+8)), so:

+2(-1k+8)

determiningTheFunctionDomain
2(-1k+8)

We multiply parentheses

-2k+16

Back to the equation:

-(-2k+16)



We get rid of parentheses

2k-16+3=0

We add all the numbers together, and all the variables

2k-13=0

We move all terms containing k to the left, all other terms to the right

2k=13

k=13/2

k=6+1/2

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