(3x-5)(3x+2)=(x-7)(9x+1)

Solution for (3x-5)(3x+2)=(x-7)(9x+1) equation:

(3x-5)(3x+2)=(x-7)(9x+1)

We move all terms to the left:

(3x-5)(3x+2)-((x-7)(9x+1))=0

We multiply parentheses ..

(+9x^2+6x-15x-10)-((x-7)(9x+1))=0


We calculate terms in parentheses: -((x-7)(9x+1)), so:

(x-7)(9x+1)

We multiply parentheses ..

(+9x^2+x-63x-7)

We get rid of parentheses

9x^2+x-63x-7

We add all the numbers together, and all the variables

9x^2-62x-7

Back to the equation:

-(9x^2-62x-7)


We get rid of parentheses

9x^2-9x^2+6x-15x+62x-10+7=0

We add all the numbers together, and all the variables

53x-3=0

We move all terms containing x to the left, all other terms to the right

53x=3

x=3/53

x=3/53