3=(j-66)/9

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Solution for 3=(j-66)/9 equation: 



3=(j-66)/9

We move all terms to the left:

3-((j-66)/9)=0

We multiply all the terms by the denominator


-((j-66)+3*9)=0



We calculate terms in parentheses: -((j-66)+3*9), so:

(j-66)+3*9

We add all the numbers together, and all the variables

(j-66)+27

We get rid of parentheses

j-66+27

We add all the numbers together, and all the variables

j-39

Back to the equation:

-(j-39)



We get rid of parentheses

-j+39=0

We add all the numbers together, and all the variables

-1j+39=0

We move all terms containing j to the left, all other terms to the right

-j=-39

j=-39/-1

j=+39

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