7(2n-2)=(3n+5)+2

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Solution for 7(2n-2)=(3n+5)+2 equation: 



7(2n-2)=(3n+5)+2

We move all terms to the left:

7(2n-2)-((3n+5)+2)=0

We multiply parentheses

14n-((3n+5)+2)-14=0



We calculate terms in parentheses: -((3n+5)+2), so:

(3n+5)+2

We get rid of parentheses

3n+5+2

We add all the numbers together, and all the variables

3n+7

Back to the equation:

-(3n+7)



We get rid of parentheses

14n-3n-7-14=0

We add all the numbers together, and all the variables

11n-21=0

We move all terms containing n to the left, all other terms to the right

11n=21

n=21/11

n=1+10/11

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