39=1/2(3x-1)(x+1)

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Solution for 39=1/2(3x-1)(x+1) equation: 



39=1/2(3x-1)(x+1)

We move all terms to the left:

39-(1/2(3x-1)(x+1))=0



Domain of the equation: 2(3x-1)(x+1))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+3x-1x-1))+39=0

We multiply all the terms by the denominator


-(1+39*2(+3x^2+3x-1x-1))=0



We calculate terms in parentheses: -(1+39*2(+3x^2+3x-1x-1)), so:

1+39*2(+3x^2+3x-1x-1)

determiningTheFunctionDomain
39*2(+3x^2+3x-1x-1)+1

Wy multiply elements

78x(++1

We use the square of the difference formula

78x(+1

Back to the equation:

-(78x(+1)



We add all the numbers together, and all the variables

-(78x1=0

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