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15x^2+6x=45
We move all terms to the left:
15x^2+6x-(45)=0
a = 15; b = 6; c = -45;
Δ = b2-4ac
Δ = 62-4·15·(-45)
Δ = 2736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2736}=\sqrt{144*19}=\sqrt{144}*\sqrt{19}=12\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12\sqrt{19}}{2*15}=\frac{-6-12\sqrt{19}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12\sqrt{19}}{2*15}=\frac{-6+12\sqrt{19}}{30} $
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