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39=1(3/10b
We move all terms to the left:
39-(1(3/10b)=0
Domain of the equation: 10b)+39!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(1(+3/10b)+39=0
We multiply all the terms by the denominator
-(1(+3=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0
Równanie nie ma rozwiązania
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