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5x-2.5+6x-3=x(2x-1)
We move all terms to the left:
5x-2.5+6x-3-(x(2x-1))=0
We add all the numbers together, and all the variables
11x-(x(2x-1))-5.5=0
We calculate terms in parentheses: -(x(2x-1)), so:We get rid of parentheses
x(2x-1)
We multiply parentheses
2x^2-1x
Back to the equation:
-(2x^2-1x)
-2x^2+11x+1x-5.5=0
We add all the numbers together, and all the variables
-2x^2+12x-5.5=0
a = -2; b = 12; c = -5.5;
Δ = b2-4ac
Δ = 122-4·(-2)·(-5.5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-10}{2*-2}=\frac{-22}{-4} =5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+10}{2*-2}=\frac{-2}{-4} =1/2 $
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