396=w(3w+3)

Solution for 396=w(3w+3) equation:

396=w(3w+3)

We move all terms to the left:

396-(w(3w+3))=0


We calculate terms in parentheses: -(w(3w+3)), so:

w(3w+3)

We multiply parentheses

3w^2+3w

Back to the equation:

-(3w^2+3w)


We get rid of parentheses

-3w^2-3w+396=0

a = -3; b = -3; c = +396;
Δ = b2-4ac
Δ = -32-4·(-3)·396
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-69}{2*-3}=\frac{-66}{-6}
=+11
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+69}{2*-3}=\frac{72}{-6}
=-12
$