-3(b-1)=11-(b+6)

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Solution for -3(b-1)=11-(b+6) equation: 



-3(b-1)=11-(b+6)

We move all terms to the left:

-3(b-1)-(11-(b+6))=0

We multiply parentheses

-3b-(11-(b+6))+3=0



We calculate terms in parentheses: -(11-(b+6)), so:

11-(b+6)

determiningTheFunctionDomain
-(b+6)+11

We get rid of parentheses

-b-6+11

We add all the numbers together, and all the variables

-1b+5

Back to the equation:

-(-1b+5)



We get rid of parentheses

-3b+1b-5+3=0

We add all the numbers together, and all the variables

-2b-2=0

We move all terms containing b to the left, all other terms to the right

-2b=2

b=2/-2

b=-1

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