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39-(2x+3)=2(x+3)+x
We move all terms to the left:
39-(2x+3)-(2(x+3)+x)=0
We get rid of parentheses
-2x-(2(x+3)+x)-3+39=0
We calculate terms in parentheses: -(2(x+3)+x), so:We add all the numbers together, and all the variables
2(x+3)+x
We add all the numbers together, and all the variables
x+2(x+3)
We multiply parentheses
x+2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
-2x-(3x+6)+36=0
We get rid of parentheses
-2x-3x-6+36=0
We add all the numbers together, and all the variables
-5x+30=0
We move all terms containing x to the left, all other terms to the right
-5x=-30
x=-30/-5
x=+6
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