39+4m=4(1+m)+5m

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Solution for 39+4m=4(1+m)+5m equation: 



39+4m=4(1+m)+5m

We move all terms to the left:

39+4m-(4(1+m)+5m)=0

We add all the numbers together, and all the variables

4m-(4(m+1)+5m)+39=0



We calculate terms in parentheses: -(4(m+1)+5m), so:

4(m+1)+5m

We add all the numbers together, and all the variables

5m+4(m+1)

We multiply parentheses

5m+4m+4

We add all the numbers together, and all the variables

9m+4

Back to the equation:

-(9m+4)



We get rid of parentheses

4m-9m-4+39=0

We add all the numbers together, and all the variables

-5m+35=0

We move all terms containing m to the left, all other terms to the right

-5m=-35

m=-35/-5

m=+7

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