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2(x-4)+x=x+9(x-3)
We move all terms to the left:
2(x-4)+x-(x+9(x-3))=0
We add all the numbers together, and all the variables
x+2(x-4)-(x+9(x-3))=0
We multiply parentheses
x+2x-(x+9(x-3))-8=0
We calculate terms in parentheses: -(x+9(x-3)), so:We add all the numbers together, and all the variables
x+9(x-3)
We multiply parentheses
x+9x-27
We add all the numbers together, and all the variables
10x-27
Back to the equation:
-(10x-27)
3x-(10x-27)-8=0
We get rid of parentheses
3x-10x+27-8=0
We add all the numbers together, and all the variables
-7x+19=0
We move all terms containing x to the left, all other terms to the right
-7x=-19
x=-19/-7
x=2+5/7
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