38=(2x+3)+(3x-5)

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Solution for 38=(2x+3)+(3x-5) equation: 



38=(2x+3)+(3x-5)

We move all terms to the left:

38-((2x+3)+(3x-5))=0



We calculate terms in parentheses: -((2x+3)+(3x-5)), so:

(2x+3)+(3x-5)

We get rid of parentheses

2x+3x+3-5

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We get rid of parentheses

-5x+2+38=0

We add all the numbers together, and all the variables

-5x+40=0

We move all terms containing x to the left, all other terms to the right

-5x=-40

x=-40/-5

x=+8

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