4z+1-z=6+2z+10

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Solution for 4z+1-z=6+2z+10 equation: 



4z+1-z=6+2z+10

We move all terms to the left:

4z+1-z-(6+2z+10)=0

We add all the numbers together, and all the variables

4z-z-(2z+16)+1=0

We add all the numbers together, and all the variables

3z-(2z+16)+1=0

We get rid of parentheses

3z-2z-16+1=0

We add all the numbers together, and all the variables

z-15=0

We move all terms containing z to the left, all other terms to the right

z=15

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