38+4y-10=14y-12-2y

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Solution for 38+4y-10=14y-12-2y equation: 



38+4y-10=14y-12-2y

We move all terms to the left:

38+4y-10-(14y-12-2y)=0

We add all the numbers together, and all the variables

4y-(12y-12)+38-10=0

We add all the numbers together, and all the variables

4y-(12y-12)+28=0

We get rid of parentheses

4y-12y+12+28=0

We add all the numbers together, and all the variables

-8y+40=0

We move all terms containing y to the left, all other terms to the right

-8y=-40

y=-40/-8

y=+5

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