38+4y-10=14y-12-12y

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Solution for 38+4y-10=14y-12-12y equation: 



38+4y-10=14y-12-12y

We move all terms to the left:

38+4y-10-(14y-12-12y)=0

We add all the numbers together, and all the variables

4y-(2y-12)+38-10=0

We add all the numbers together, and all the variables

4y-(2y-12)+28=0

We get rid of parentheses

4y-2y+12+28=0

We add all the numbers together, and all the variables

2y+40=0

We move all terms containing y to the left, all other terms to the right

2y=-40

y=-40/2

y=-20

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