38+(3x-8)+(4x+18)=180

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Solution for 38+(3x-8)+(4x+18)=180 equation: 



38+(3x-8)+(4x+18)=180

We move all terms to the left:

38+(3x-8)+(4x+18)-(180)=0

We add all the numbers together, and all the variables

(3x-8)+(4x+18)-142=0

We get rid of parentheses

3x+4x-8+18-142=0

We add all the numbers together, and all the variables

7x-132=0

We move all terms containing x to the left, all other terms to the right

7x=132

x=132/7

x=18+6/7

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