36x2+x-220=x+5

Solution for 36x2+x-220=x+5 equation:

36x^2+x-220=x+5

We move all terms to the left:

36x^2+x-220-(x+5)=0

We get rid of parentheses

36x^2+x-x-5-220=0

We add all the numbers together, and all the variables

36x^2-225=0

a = 36; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·36·(-225)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*36}=\frac{-180}{72}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*36}=\frac{180}{72}
=2+1/2
$