36x-18(x-2)=9(x+3)+10

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Solution for 36x-18(x-2)=9(x+3)+10 equation: 



36x-18(x-2)=9(x+3)+10

We move all terms to the left:

36x-18(x-2)-(9(x+3)+10)=0

We multiply parentheses

36x-18x-(9(x+3)+10)+36=0



We calculate terms in parentheses: -(9(x+3)+10), so:

9(x+3)+10

We multiply parentheses

9x+27+10

We add all the numbers together, and all the variables

9x+37

Back to the equation:

-(9x+37)



We add all the numbers together, and all the variables

18x-(9x+37)+36=0

We get rid of parentheses

18x-9x-37+36=0

We add all the numbers together, and all the variables

9x-1=0

We move all terms containing x to the left, all other terms to the right

9x=1

x=1/9

x=1/9

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